The subtle mistake is caused by reviewers ignoring the uniqueness requirement for the
application of corollary III of the division algorithm. Ignoring the uniqueness
requirement leads to the erroneous conclusion that FLT65 is wrong as follows:
The reviewer
reasons: “FLT65 correctly shows that when f(Z),
an algebraic polynomial of degree p-1 in Z, is divided by Z – a, a factor of Y1,
the remainder is f(a) = an-1+X1an-2+…+X1n-1. And FLT65 also correctly states that f(a) cannot equal zero because a and X1 are
positive integers if the x, y and z of the Fermat equation are positive
integers, but corollary III says f(Z)
is divisible by Z – a, if, and only
if, f(a) = 0. And we know that this is true for algebraic polynomials, but we can find
integers, a, X and Z, such that the integer value of f(Z) is divisible by the integer value of Z – a, even though f(a)
is not equal to zero. Therefore, FLT65 is wrong!”
This reasoning sounds quite convincing until you realize
that the uniqueness requirement has
been ignored. What corollary III actually says, as quoted in FLT65, is that
“if
q(Z) and r(Z) are unique, f(a) cannot contain Z - a, and so it follows that a polynomial, f(Z), of degree greater than 1, is
divisible by Z - a IF AND ONLY IF, f(a) = 0. “
The quotient and
remainder are unique only when the remainder has the minimum value of either
zero, or less than Z – a, and the
author has shown above that for the examples, and for any integers a, X and Z, the unique remainder and quotient
can only occur when a is a
non-integer.
The proof of
corollary III depends on the uniqueness of the quotient and remainder with
division of f(Z) by Z – a for any specific integer value
of x = X1. The uniqueness
requirement for application of the corollary is clearly stated in FLT65, and
the complete proof is attached in Appendix A. Note
that the use of X as the variable in
the proof of the division algorithm and corollaries in FLT65 is arbitrary and follows the generic practice of using X for the variable unless other letters
or symbols are needed for clarity. The variable Z is used in these discussions to conform to its usage in the FLT
equation.
In the examples
mistakenly thought to be counterexamples disproving FLT65, the quotient and
remainder only become unique when f(a)
reaches its minimum value and the quotient reaches its maximum in the repeated
division of the remainder (which must contain Z – a if there are integer solutions for the FLT equation) by Z – a = ai-1 – ai.
When the unique minimum remainder and maximum quotient for a given X1 are reached, and the
value of Z – a is identical with the
integer factor obtained by substituting the unique values of ai-1 and ai, for Z and a, corollary III applies and f(a) ≠
0 implies f(Z) cannot contain Z – a or its integer value, as a factor, and FLT
is proved.
See Appendix E for complete details.
This contradiction proving FLT is
made obvious by the repetitive division of the remainder by Z - a, a process of
infinite descent, which was a favorite
method used by Fermat.[17]
Thus, Pierre de Fermat’s claim that
he had found a ‘marvelous’ proof, may be vindicated, as the FLT65 concepts were
certainly available to Fermat in 1637.
CONCLUSION:
The only significant objections to FLT65, raised by
mathematicians who have reviewed it, are based on the hypothesis that the
division algorithm which applies to algebraic polynomials, might not apply to
integer polynomials formed by integer solutions of the Fermat equation, if there are any.
Some reviewers have jumped to the conclusion that this
concern reveals a fatal flaw in FLT65, because one can find integer values for X, a and Z that produce values of Z
– a that divide f(Z), even
though the remainder f(a) is not
zero, seeming to contradict corollary III of the division algorithm. However,
this is a subtle misdirection of logic made by reviewers who have ignored the uniqueness requirement for application of corollary III. As stated in the
proof of Corollaries II and III in FLT65: if q(Z) and r(Z) are unique, f(a) cannot contain Z – a, and so
it follows that a polynomial f(Z) of
degree greater than one is divisible by Z –a, IF AND ONLY IF, f(a) = 0.
So we see that corollary III is not actually violated by the
reviewers’ examples. The integers chosen in such examples do not produce valid
counterexamples because, as shown above, they do not produce unique values for q(Z) and F(a). The fact that integers are closed with respect to addition
applied to the integer equation f(Z)/(Z – a)
= q(Z)+ f(a)/(Z – a) implies that because f(Z) contains (Z – a)n, f(a) must also contain Z – a, but when q(Z) and F(a) are unique, as they must be
for an integer solution to the Fermat equation, we have an unavoidable
contradiction proving that, if X and Y are integers, a cannot be an integer, implying that Z cannot be an integer, proving FLT.
The hypothesis that the division algorithm might not apply
to integer polynomials is falsified in two independent ways:
(1.) the division
algorithm expresses a basic mathematical relationship that applies to all polynomials composed of elements of the field of real
numbers, including the integers. This means that integer polynomials
derived from integer solutions of the FLT equation must conform to the division
algorithm and its corollaries.
(2.) The author demonstrates in Appendix E by the method of
infinite descent that the argument that f(z)
may be divisible by Z – a for some
integer values of Z, is simply
irrelevant. The attempted counterexamples fail because, if there are integers that satisfy the Fermat equation, they must also
satisfy the mathematical relationship between the integer polynomials formed by
factoring the Fermat equation. The resulting factors are algebraic
polynomials, and thus the division algorithm applies to them. As integer
polynomials, they comprise a subset of the real number polynomials formed by
the p
real number solutions of the Fermat equation.
This
means that f(z)g(z) =Ap(z –
a)p = Yp, a condition that is necessary if there are
integer solutions, can only be true if z
= a, which produces the trivial solution with Y = 0, or if a is a
non-integer. (See
Appendix F.) If a is a
non-integer, Y, which contains Z – a, cannot be an integer, producing
an unresolvable contradiction. So, the fact that f(a) ≠ 0 when f(Z) is
divided by Z - a, actually proves
that the equation xn + yn
= zn, where n is a prime > 2, has
no solution in integers, as stated in FLT65.
The author’s position has been, and remains, that FLT65, his
1965 proof, is conclusive and complete. He maintains this position for two
simple reasons:
(1.) The division algorithm and corollaries applied in the
proof are valid for polynomials over the entire field [1] of real numbers,
which includes the integers, and
(2.) Application of the division algorithm to the FLT equation
produces a unique remainder that allows us to determine the numerical type of
the third variable when two of them are assumed to be integers (Appendix F),
and except for one trivial solution, that type is non-integer.
_________
[1] In
mathematics, a field is a group
of ordered quantitative elements that
contains a multiplicative
inverse for every nonzero element. As such it is an arithmetical structure within which
the operations of addition, subtraction, multiplication,
and division are consistent and valid, and it supports an algebraic
structure within which the same basic operations are valid. Geometrically, a
field is a dimensional domain within which arithmetically and algebraically defined elements can be described and located.
The three most basic mathematical fields are the field of real numbers, the
field of rational numbers, which
include integers, and the field of complex
numbers.
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